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CAPM Practice: Demonstrate an understanding of a project management plan schedule

Question 74 of 85 in Demonstrate an understanding of a project management plan schedule

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A project manager discovers that the cost to crash Activity X by 3 days is $15,000 ($5,000/day), and the cost to crash Activity Y by 2 days is $12,000 ($6,000/day). Both are on the critical path. To save 2 days of project time at the LOWEST cost, which activity should she crash?
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Correct answer: Activity X — it costs $5,000/day, which is cheaper than Activity Y's $6,000/day

Explanation

When crashing, always select the least expensive option first. Activity X costs $5,000/day to crash; Activity Y costs $6,000/day. To save 2 days, crash Activity X for 2 days at $10,000 total — cheaper than crashing Activity Y for 2 days at $12,000 total. The crashing decision should always optimize cost per unit of duration saved.

**Why not A:** Fast tracking is not always cheaper than crashing. Fast tracking involves executing activities in parallel that were originally planned sequentially, which introduces risk of rework. The question requires comparing specific costs, and Activity X at $5,000/day is the least expensive crashing option.

**Why not B:** Crashing both activities equally is unnecessary and more expensive. Only 2 days need to be saved, and Activity X is cheaper per day. There is no reason to split the crashing across both activities when one is clearly more cost-effective.

**Why not D:** Having fewer days available to crash does not make Activity Y the better choice. The decision should be based on cost per day of duration saved. Activity Y costs $6,000/day versus Activity X at $5,000/day, making Activity X the more economical option for saving 2 days.

Key Concept

This question covers Demonstrate an understanding of a project management plan schedule under Demonstrate an understanding of a project management plan schedule (Predictive, Plan-Based Methodologies).

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